Community
Semicircle in a square (Discussion)
5 Responses
-
Peter Blomert said – Sat, 05 Jul 2008 15:05:10 -0000 ( Link )
Be x the radius of the maximal semicircle and be a the length of the square (=1 for the unit square), then x + x/sqrt(2) = a
So for the unit square:
x = sqrt(2)/(1+sqrt(2)) —> the area of the semicircle of the unit square equals 0.539 square units
- Actions
- Author
- Peter Blomert
-
Post Comments
-
Peter Blomert said – Mon, 14 Jul 2008 10:02:32 -0000 ( Link )
have a look at this picture – it will explain the idea. The semicircle lies axially symmetrical to one diagonal of the square. From this follows that the length of the square has to be x + x/sqrt(2). With a given length a you now can rather easily figure out x.
- Actions
- Author
- Peter Blomert
-
Post Comments
-
Post Comments
-
Post Comments
Top Related Content
Advertisement
- 3 Views
- 5 Responses
Post Comments