Jump To Content

LearnHub

Mathguru

Community

Mathguru

Primary Navigation

algebra (Discussion)

shashank_gaur said – Sun, 01 Mar 2009 15:21:50 -0000 ( Link )

solve x3=i , where i2=-1

Actions
Author
shashank_gaur
shashank_gaur
Authority 11
Vote
Current Rating
0
Rate Up
Rate Down
No Votes

3 Responses

  1. shashank_gaur said – Mon, 02 Mar 2009 02:06:21 -0000 ( Link )

    x3 =i where i2 = -1

    Actions
    Author
    shashank_gaur
    shashank_gaur
    Authority 11
    Vote
    Current Rating
    0
    Rate Up
    Rate Down
    No Votes

    Post Comments

  2. shashank_gaur said – Mon, 02 Mar 2009 02:07:40 -0000 ( Link )

    x cube = iota

    Actions
    Author
    shashank_gaur
    shashank_gaur
    Authority 11
    Vote
    Current Rating
    0
    Rate Up
    Rate Down
    No Votes

    Post Comments

  3. raj beniwal said – Thu, 13 Aug 2009 15:50:57 -0000 ( Link )

    if we put x = i1/3. x2 = i2/3.==(i2)1/3. =>(-1)1/3=X2. =>now X=(-1)1/6

    Actions
    Author
    raj beniwal
    raj beniwal
    Authority 82
    Vote
    Current Rating
    1
    Rate Up
    Rate Down
    1 Total Vote

    Post Comments

Your Response
Textile is Enabled (View Reference)

Top Related Content

Information

Related Discussions

Related Content